Seção II: Ângulos ⇒ Problema 148 - Linhas Retas e Ângulos-Vol. 1 Tópico resolvido

[petrasMOD]

Se [tex3]m \parallel n[/tex3] calcular x^o.

[tex3]\alpha+\beta +\theta +w = 250^o [/tex3]

Resposta

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Gabarito: B) 70^o

[petrasMOD]

[tex3]\angle CAB= 180-(w+\alpha)\\
\angle GFE = 180-(\theta+w) \\
\therefore \angle FHA = \angle WHI = 180- [180-(w+\alpha)+180-(\theta+w)] =\alpha+2w+\theta-180^o \\
DIHJ: 180-x+180-w + \beta+\angle WHI =360^o \\
-x-w+b+\alpha+2w+\theta -180^o =0 \implies x = \underbrace{\alpha+\beta+\theta+w}_{250^o}-180^o\\
\therefore \boxed{x = 70^o }
[/tex3]