Pré-Vestibular ⇒ (Unifor-CE) Funções Tg, Cot, Sec, Coscante Tópico resolvido

[Taísa]

O valor de tg150°+2.sen120°-cos330° é igual a:

[SirTcgm]

[tex3]\text{tg}150^{\circ}=-\text{tg}30^{\circ}=-\frac{\sqrt{3}}{3}[/tex3]
[tex3]\text{sen}120^{\circ}=\text{sen}60^{\circ}=\frac{\sqrt{3}}{2}[/tex3]
[tex3]\text{cos}330^{\circ}=\text{cos}30^{\circ}=\frac{\sqrt{3}}{2}[/tex3]
[tex3]\text{tg}150^{\circ}+2\cdot \text{sen}120^{\circ}-\text{cos}330^{\circ}[/tex3]
[tex3]\Rightarrow -\frac{\sqrt{3}}{3}+\frac{2\sqrt{3}}{2}-\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}-\frac{\sqrt{3}}{3}[/tex3]
[tex3]\Rightarrow \frac{3\sqrt{3}-2\sqrt{3}}{6}=\frac{\sqrt{3}}{6}[/tex3]
[tex3]\boxed{\boxed{\text{tg}150^{\circ}+2\cdot \text{sen}120^{\circ}-\text{cos}330^{\circ}=\frac{\sqrt{3}}{6}}}[/tex3]

TM