Radiciação
Enviado: 28 Nov 2006, 10:11
Calcule:
[tex3](\sqrt {2} +\sqrt {7})^2[/tex3]
[tex3](\sqrt {2} +\sqrt {7})^2[/tex3]
[tex3](a+b)^2=a^2+b^2+2ab[/tex3] --> [tex3](\sqrt{2}+\sqrt{7})^2=(\sqrt{2})^2+(\sqrt{7}^2)+2\sqrt{2}.\sqrt{7}[/tex3]
[tex3](\sqrt{2}+\sqrt{7})^2=(2+7+2\sqrt{14})[/tex3]
[tex3](\sqrt{2}+\sqrt{7})^2=(9+2\sqrt{14})[/tex3]