carmelita,
R = receita
C=custo
p =produção
t = transporte
[tex3]
\mathrm{R_A=10x\\
C_{A(p)} =8x\\
C_{A(t)}=0,4x \\
R_B=7y\\
C_{B(p)} =5y\\
C_{B(t)}=0,6y \\
8x+5y \leq 5000 (I)\\
0,4x+0,6y \leq 300 \implies 2x+3y \leq 1500(II)\\
4(II)-(I) = 7y = 1000 \therefore \boxed{y \approx 142,86}\color{green}\checkmark\\
2x+3.\frac{1000}{7} =1500 \implies \boxed{x\approx535,71}\color{green}\checkmark
}[/tex3]...