Estude! Com Prof. Caju

A área do triângulo ABC, conforme a figura, é:
A) [tex3]\sqrt{3}[/tex3]
B) [tex3]2 \sqrt{3}[/tex3]
C) [tex3]3[/tex3]
D) [tex3]4 \sqrt{3}[/tex3]
E) [tex3]6[/tex3]

@Gabeds,
[tex3] sen 60^o = \frac{h}{4}= \frac{\sqrt3}{2} = 6 \therefore h = 2\sqrt3\\
S = \frac{1}{2}(\sqrt3.2\sqrt3) = \boxed{3} [/tex3]